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2t^2-15t-70=0
a = 2; b = -15; c = -70;
Δ = b2-4ac
Δ = -152-4·2·(-70)
Δ = 785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{785}}{2*2}=\frac{15-\sqrt{785}}{4} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{785}}{2*2}=\frac{15+\sqrt{785}}{4} $
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